Posted 2017-May-04, 05:44
A slightly offbeat but completely sound method:
==
2♣ = 5 card major Stayman
... - 2♦ = no 5 card major
... - ... - 2♥ = asks about spades and range, no interest in hearts
... - ... - 2♠ = 4 hearts, no interest in spades
... - ... - 2NT = 4♥4♠, INV
... - ... - 3♣ = 4+♥4+♠, GF
... - ... - 3♦ = 5+♦, 4 card major, SI
... - ... - 3♥ = 5+♣4♦, SI
... - ... - 3♠ = 5+♦4♣, SI
... - 2M = 5 card major
2♦ = 5+ hearts
2♥ = 5+ spades
2♠ = range ask
... - 2NT = min
... - ... - 3♣ = weak with long clubs
... - ... - 3♦ = 5+♣4♥, GF
... - ... - 3♥ = 5+♣4♠, GF
... - ... - 3♠ = 5+♣5+♦, GF
... - 3♣ = max
... - ... - P = weak with long clubs
... - ... - 3♦ = 5+♣4♥, GF
... - ... - 3♥ = 5+♣4♠, GF
... - ... - 3♠ = 5+♣5+♦, GF
2NT = 5♠4♥, INV
3m = nat, SI
3M = GF 3-suiters
The invites with a long, broken minor are given up for both suits to accomodate this.
When I played regular Stayman I used a 3 suit transfer method so this is one to consider for your case of 2NT vbeing natural. By this I mean that 2♠ shows clubs but that diamond-based hands go through 2♣. There is just enough space to allow for this if you jiggle things around appropriately and it makes for a relatively efficient structure (although thia use of 2NT suggests that efficiency is not exactly high on your priority list!).
(-: Zel :-)